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Pair of straight lines

1. Combined Equation of a Pair of Lines

  • Joint Equation:

    The equation $uv = 0$ represents the combined (or joint) equation of the lines $u = 0$ and $v = 0$.

v = 0 u = 0 P ( x 1 , y 1 ) Q ( x 2 , y 2 )
Intersecting Lines u=0 and v=0

2. Homogeneous Equation of Degree Two

  • Standard Form:

    $ax^2 + 2hxy + by^2 = 0$ represents a pair of lines passing through the origin if $h^2 - ab \geq 0$.

  • Slopes of the Lines ($m_1, m_2$):

    $$m_1 = \frac{-h - \sqrt{h^2 - ab}}{b}, \quad m_2 = \frac{-h + \sqrt{h^2 - ab}}{b}$$

  • Sum and Product of Slopes:

    $$m_1 + m_2 = -\frac{2h}{b}, \quad m_1m_2 = \frac{a}{b}$$

  • Auxiliary Equation:

    $bm^2 + 2hm + a = 0$ (Roots are the slopes $m_1$ and $m_2$).

3. Angle Between the Lines

X Y y = m 1 x y = m 2 x θ O
Angle Between Lines passing through Origin
  • Acute Angle ($\theta$):

    If $\theta$ is the acute angle between the lines $ax^2 + 2hxy + by^2 = 0$, then:

    $$\tan \theta = \left|\frac{2\sqrt{h^2 - ab}}{a + b}\right|$$

  • Condition for Coincident Lines:

    $h^2 - ab = 0$ (or $h^2 = ab$).

  • Condition for Perpendicular Lines:

    $a + b = 0$.

  • Condition for Distinct Lines:

    $h^2 - ab > 0$.

4. General Second Degree Equation

  • Standard Form:

    $ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0$

  • Necessary Conditions to Represent a Pair of Lines:
    • 1. $abc + 2fgh - af^2 - bg^2 - ch^2 = 0$
    • 2. $h^2 - ab \geq 0$
  • Determinant Form of the Condition:

    $$\begin{vmatrix} a & h & g \\ h & b & f \\ g & f & c \end{vmatrix} = 0$$

  • Point of Intersection:

    If the general equation represents intersecting lines ($h^2 - ab > 0$), their point of intersection is:

    $$\left( \frac{hf - bg}{ab - h^2}, \frac{gh - af}{ab - h^2} \right)$$

5. Important Additional Properties

  • Bisectors of Angles:

    The joint equation of the bisectors of the angles between the lines $ax^2 + 2hxy + by^2 = 0$ is:

    $$hx^2 - (a-b)xy - hy^2 = 0$$

  • Perpendicular Pair:

    The combined equation of the pair of lines passing through the origin and perpendicular to the lines represented by $ax^2 + 2hxy + by^2 = 0$ is:

    $$bx^2 - 2hxy + ay^2 = 0$$

  • Product of Perpendiculars:

    The product of lengths of perpendiculars drawn from $P(x_1, y_1)$ to the lines $ax^2 + 2hxy + by^2 = 0$ is:

    $$\left|\frac{ax_1^2 + 2hx_1y_1 + by_1^2}{\sqrt{(a-b)^2 + 4h^2}}\right|$$